我想提取：
- 从下面的文字SRC
image标签和 - 锚标签的文本是里面
div类数据
我成功设法提取IMG SRC，但我有麻烦提取锚标记上的文字。
<a class="title" href="http://www.amazon.com/Nikon-COOLPIX-Digital-Camera-NIKKOR/dp/B0073HSK0K/ref=sr_1_1?s=electronics&ie=UTF8&qid=1343628292&sr=1-1&keywords=digital+camera">Nikon COOLPIX L26 16.1 MP Digital Camera with 5x Zoom NIKKOR Glass Lens and 3-inch LCD (Red)</a>
这里是链接整个HTML页面 。
这里是我的代码：
for div in soup.findAll('div', attrs={'class':'image'}):
print "\n"
for data in div.findNextSibling('div', attrs={'class':'data'}):
for a in data.findAll('a', attrs={'class':'title'}):
print a.text
for img in div.findAll('img'):
print img['src']
我所试图做的是提取图像SRC（链接），里面的标题div class=data ，因此，例如：
<a class="title" href="http://www.amazon.com/Nikon-COOLPIX-Digital-Camera-NIKKOR/dp/B0073HSK0K/ref=sr_1_1?s=electronics&ie=UTF8&qid=1343628292&sr=1-1&keywords=digital+camera">Nikon COOLPIX L26 16.1 MP Digital Camera with 5x Zoom NIKKOR Glass Lens and 3-inch LCD (Red)</a>
应提取：
Nikon COOLPIX L26 16.1 MP Digital Camera with 5x Zoom NIKKOR Glass Lens and 3-inch LCD (Red)
这将帮助：
from bs4 import BeautifulSoup
data = '''<div class="image">
<a href="http://www.example.com/eg1">Content1<img
src="http://image.example.com/img1.jpg" /></a>
</div>
<div class="image">
<a href="http://www.example.com/eg2">Content2<img
src="http://image.example.com/img2.jpg" /> </a>
</div>'''
soup = BeautifulSoup(data)
for div in soup.findAll('div', attrs={'class':'image'}):
print(div.find('a')['href'])
print(div.find('a').contents[0])
print(div.find('img')['src'])
如果您正在寻找进入亚马逊产品，那么你应该使用官方的API。 至少有一个Python包 ，这将缓解你刮的问题和使用条款中保留您的活动。
在我的情况下，它的工作这样的：
from BeautifulSoup import BeautifulSoup as bs
url="http://blabla.com"
soup = bs(urllib.urlopen(url))
for link in soup.findAll('a'):
print link.string
希望能帮助到你！
我建议去了LXML路线和使用XPath。
from lxml import etree
# data is the variable containing the html
data = etree.HTML(data)
anchor = data.xpath('//a[@class="title"]/text()')
以上所有的答案真的帮我建立我的答案，因为这样我投所有的答案，其他用户把它拿出来：但我终于凑齐了我自己的答案，我正在处理确切的问题：
由于问题明确规定，我不得不进入一些兄弟姐妹及其子女在DOM结构：该解决方案将遍历图像中的DOM结构，并使用产品标题构建映像名称和图像保存到本地目录。
import urlparse
from urllib2 import urlopen
from urllib import urlretrieve
from BeautifulSoup import BeautifulSoup as bs
import requests
def getImages(url):
#Download the images
r = requests.get(url)
html = r.text
soup = bs(html)
output_folder = '~/amazon'
#extracting the images that in div(s)
for div in soup.findAll('div', attrs={'class':'image'}):
modified_file_name = None
try:
#getting the data div using findNext
nextDiv = div.findNext('div', attrs={'class':'data'})
#use findNext again on previous object to get to the anchor tag
fileName = nextDiv.findNext('a').text
modified_file_name = fileName.replace(' ','-') + '.jpg'
except TypeError:
print 'skip'
imageUrl = div.find('img')['src']
outputPath = os.path.join(output_folder, modified_file_name)
urlretrieve(imageUrl, outputPath)
if __name__=='__main__':
url = r'http://www.amazon.com/s/ref=sr_pg_1?rh=n%3A172282%2Ck%3Adigital+camera&keywords=digital+camera&ie=UTF8&qid=1343600585'
getImages(url)
>>> txt = '<a class="title" href="http://rads.stackoverflow.com/amzn/click/B0073HSK0K">Nikon COOLPIX L26 16.1 MP Digital Camera with 5x Zoom NIKKOR Glass Lens and 3-inch LCD (Red)</a> '
>>> fragment = bs4.BeautifulSoup(txt)
>>> fragment
<a class="title" href="http://rads.stackoverflow.com/amzn/click/B0073HSK0K">Nikon COOLPIX L26 16.1 MP Digital Camera with 5x Zoom NIKKOR Glass Lens and 3-inch LCD (Red)</a>
>>> fragment.find('a', {'class': 'title'})
<a class="title" href="http://rads.stackoverflow.com/amzn/click/B0073HSK0K">Nikon COOLPIX L26 16.1 MP Digital Camera with 5x Zoom NIKKOR Glass Lens and 3-inch LCD (Red)</a>
>>> fragment.find('a', {'class': 'title'}).string
u'Nikon COOLPIX L26 16.1 MP Digital Camera with 5x Zoom NIKKOR Glass Lens and 3-inch LCD (Red)'
