Sample data
CREATE TABLE test
(id integer, session_ID integer, value integer)
;
INSERT INTO test
(id, session_ID, value)
VALUES
(0, 2, 100),
(1, 2, 120),
(2, 2, 140),
(3, 1, 900),
(4, 1, 800),
(5, 1, 500)
;
Current query
select
id,
last_value(value) over (partition by session_ID order by id) as last_value_window,
last_value(value) over (partition by session_ID order by id desc) as last_value_window_desc
from test
ORDER BY id
I was running into a problem with the last_value()
window function:
http://sqlfiddle.com/#!15/bcec0/2
In the fiddle I am trying to work with the sort direction within the last_value()
query.
Edit:
The question is not: Why I don't get the all time last value and how to use the frame clause (unbounded preceding
and unbounded following
). I know about the difference of first_value(desc)
and last_value()
and the problem that last_value()
does not give you the all-time last value:
The default frame clause is unbounded preceding until current row. So first value is always giving the first row withing the clause. So it doesn't matter if there is just one row (the frame clause includes only this one) or one hundered (the frame clause includes all hundred). The result is always the first one. In DESC order it is the same: DESC changes the sort order and then the first row is the last value, no matter how many rows you get.
With last_value()
the behavior is very similar: If you have one row, it gives you the last value of the default frame clause: This one row. At the second row, the frame clause contains the two rows, the last one is the second. That's why last_value()
does not give you the last row of all rows but only the last row until the current row.
But if I change the order to DESC I am expecting that I have the last row of all first, so I get this one at the first row, than the last but second one at the second row and so on. But that's not the result. Why?
For the current example these are the results for first_value()
, first_value(desc)
, last_value()
, last_value(desc)
and what I am expecting for the last_value(desc)
:
id | fv_asc | fv_desc | lv_asc | lv_desc | lv_desc(expecting)
----+--------+---------+--------+---------+--------------------
0 | 100 | 140 | 100 | 100 | 140
1 | 100 | 140 | 120 | 120 | 120
2 | 100 | 140 | 140 | 140 | 100
3 | 900 | 500 | 900 | 900 | 500
4 | 900 | 500 | 800 | 800 | 800
5 | 900 | 500 | 500 | 500 | 900
For me it seems that the ORDER BY DESC
flag is ignored within the default frame clause last_value()
call. But it is not within the first_value()
call. So my question is: Why is the last_value()
result the same as the last_value(desc)
?
The problem with LAST_VALUE()
is that the default rules for windowing clauses remove the values that you really want. This is a very subtle problem and is true in all databases that support this functionality.
This comes from an Oracle blog:
Whilst we are on the topic of windowing clauses, the implicit and
unchangeable window clause for the FIRST and LAST functions is ROWS
BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING, in other words
all rows in our partition. For FIRST_VALUE and LAST_VALUE the default
but changeable windowing clause is ROWS BETWEEN UNBOUNDED PRECEDING
AND CURRENT ROW, in other words we exclude rows after the current one.
Dropping rows off the bottom of a list makes no difference when we are
looking for the first row in the list (FIRST_VALUE) but it does make a
difference when we are looking for the last row in the list
(LAST_VALUE) so you will usually need either to specify ROWS BETWEEN
UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING explicitly when using
LAST_VALUE or just use FIRST_VALUE and reverse the sort order.
Hence, just use FIRST_VALUE()
. This does what you want:
with test (id, session_ID, value) as (
(VALUES (0, 2, 100),
(1, 2, 120),
(2, 2, 140),
(3, 1, 900),
(4, 1, 800),
(5, 1, 500)
)
)
select id,
first_value(value) over (partition by session_ID order by id) as first_value_window,
first_value(value) over (partition by session_ID order by id desc) as first_value_window_desc
from test
order by id
After one year I have got the solution:
Take this statement:
SELECT
id,
array_accum(value) over (partition BY session_ID ORDER BY id) AS window_asc,
first_value(value) over (partition BY session_ID ORDER BY id) AS first_value_window_asc,
last_value(value) over (partition BY session_ID ORDER BY id) AS last_value_window_asc,
array_accum(value) over (partition BY session_ID ORDER BY id DESC) AS window_desc,
first_value(value) over (partition BY session_ID ORDER BY id DESC) AS first_value_window_desc,
last_value(value) over (partition BY session_ID ORDER BY id DESC) AS last_value_window_desc
FROM
test
ORDER BY
id
This gives
id window_asc first_value_window_asc last_value_window_asc window_desc first_value_window_desc last_value_window_desc
-- ------------- ---------------------- --------------------- ------------- ----------------------- ----------------------
0 {100} 100 100 {140,120,100} 140 100
1 {100,120} 100 120 {140,120} 140 120
2 {100,120,140} 100 140 {140} 140 140
3 {900} 900 900 {500,800,900} 500 900
4 {900,800} 900 800 {500,800} 500 800
5 {900,800,500} 900 500 {500} 500 500
The array_accum
shows the used window. There you can see the first and the current last value of the window.
What happenes shows the execution plan:
"Sort (cost=444.23..449.08 rows=1940 width=12)"
" Sort Key: id"
" -> WindowAgg (cost=289.78..338.28 rows=1940 width=12)"
" -> Sort (cost=289.78..294.63 rows=1940 width=12)"
" Sort Key: session_id, id"
" -> WindowAgg (cost=135.34..183.84 rows=1940 width=12)"
" -> Sort (cost=135.34..140.19 rows=1940 width=12)"
" Sort Key: session_id, id"
" -> Seq Scan on test (cost=0.00..29.40 rows=1940 width=12)"
There you can see: First there is an ORDER BY id
for the first three window functions.
This gives (as stated in question)
id window_asc first_value_window_asc last_value_window_asc
-- ------------- ---------------------- ---------------------
3 {900} 900 900
4 {900,800} 900 800
5 {900,800,500} 900 500
0 {100} 100 100
1 {100,120} 100 120
2 {100,120,140} 100 140
Then you can see another sort: ORDER BY id DESC
for the next three window functions. This sort gives:
id window_asc first_value_window_asc last_value_window_asc
-- ------------- ---------------------- ---------------------
5 {900,800,500} 900 500
4 {900,800} 900 800
3 {900} 900 900
2 {100,120,140} 100 140
1 {100,120} 100 120
0 {100} 100 100
With this sorting the DESC
window function are executed. The array_accum
column shows the resulting windows:
id window_desc
-- -------------
5 {500}
4 {500,800}
3 {500,800,900}
2 {140}
1 {140,120}
0 {140,120,100}
The resulting (first_value DESC
and) last_value DESC
is now absolutely identical to the last_value ASC
:
id window_asc last_value_window_asc window_desc last_value_window_desc
-- ------------- --------------------- ------------- ----------------------
5 {900,800,500} 500 {500} 500
4 {900,800} 800 {500,800} 800
3 {900} 900 {500,800,900} 900
2 {100,120,140} 140 {140} 140
1 {100,120} 120 {140,120} 120
0 {100} 100 {140,120,100} 100
Now it became clear to me why last_value ASC
is equal to last_value DESC
. It's because the second ORDER
of the window functions which gives an inverted window.
(The last sort of the execution plan ist the last ORDER BY
of the statement.)
As a little bonus: This query shows a little optimization potential: If you call the DESC
windows first and then the ASC
ones you do not need the third sort. It is in the right sort at this moment.
Check how the window frame is defined. This example might help:
select
id,
last_value(value) over (
partition by session_id
order by id
) as lv_asc,
last_value(value) over (
partition by session_id
order by id desc
) as lv_desc,
last_value(value) over (
partition by session_id
order by id
rows between unbounded preceding and unbounded following
) as lv_asc_unbounded,
last_value(value) over (
partition by session_id
order by id desc
rows between unbounded preceding and unbounded following
) as lv_desc_unbounded
from t
order by id;
id | lv_asc | lv_desc | lv_asc_unbounded | lv_desc_unbounded
----+--------+---------+------------------+-------------------
0 | 100 | 100 | 140 | 100
1 | 120 | 120 | 140 | 100
2 | 140 | 140 | 140 | 100
3 | 900 | 900 | 500 | 900
4 | 800 | 800 | 500 | 900
5 | 500 | 500 | 500 | 900