Ajax upload not working codeigniter

2019-01-12 08:02发布

站内文章 / JavaScript

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叛逆

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问题:

I am using codeigniter 3.1 . I want to post upload data using ajax.

Ajax upload file not working. But when i post the simple form without ajax, it working fine.

I don't know why but no error in console.

HTML

  <?php echo form_open_multipart(site_url("upload/post"), ['id' => 'uploader']) ?>
    <input type="file" name="userfile" value="">
    <input type="submit" value="Submit" />
  <?php echo form_close() ?>

JAVASCRIPT

   $('#uploader').submit(function (event) {
            event.preventDefault();
            $.ajax({
                url: window.location.href + '/post',
                type: "POST",
                dataType: 'json',
                data: new FormData(this)
               });
      });

CONTROLLERS

 public function post() 
    {
        $this->load->helper('url');
        $this->load->helper('form');
        $this->load->library("upload");
        $file = $this->common->nohtml($this->input->post("userfile"));

        $this->upload->initialize(array( 
               "upload_path" => 'upload',
               "overwrite" => FALSE,
               "max_filename" => 300,
               "encrypt_name" => TRUE
            ));

        $this->upload->do_upload('userfile');

        $data = $this->upload->data();

        $image_file = $data['file_name'];

  }

回答1:

One of the issues is that file uploading uses a different mechanism than the other form <input> types. That is why $this->input->post("userfile") isn't getting the job done for you. Other answers have suggested using javascript's FormData and this one does too.

HTML

A very simple form for picking a file and submitting it. Note the change from a simple button to <input type="submit".... Doing so makes it a lot easier for the javascript to use the FormData object.

FormData documentation

<!DOCTYPE html>
<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
        <script src="https://code.jquery.com/jquery-2.2.2.js"></script>
        <title>Upload Test</title>
    </head>
    <body>

        <?= form_open_multipart("upload/post", ['id' => 'uploader']); ?>
        <input type="file" name="userfile">
        <p>
            <input type="submit" value="Upload">
        </p>
        <?php echo form_close() ?>

        <div id="message"></div>

        <script>
            $('#uploader').submit(function (event) {
                event.preventDefault();
                $.ajax({
                    url: window.location.href + '/post',
                    type: "POST",
                    dataType: 'json',
                    data: new FormData(this),
                    processData: false,
                    contentType: false,
                    success: function (data) {
                        console.log(data);
                        if (data.result === true) {
                            $("#message").html("<p>File Upload Succeeded</p>");
                        } else {
                            $("#message").html("<p>File Upload Failed!</p>");
                        }
                        $("#message").append(data.message);
                    }
                });
            });
        </script>
    </body>
</html>

JAVASCRIPT

Use FormData to capture the fields. Note that instead of handling the button click we handle the submit event.

$('#uploader').submit(function (event) {
    event.preventDefault();
    $.ajax({
        url: window.location.href + '/post',
        type: "POST",
        dataType: 'json',
        data: new FormData(this),
        processData: false,
        contentType: false,
        success: function (data) {
            //uncomment the next line to log the returned data in the javascript console
            // console.log(data);
            if (data.result === true) {
                $("#message").html("<p>File Upload Succeeded</p>");
            } else {
                $("#message").html("<p>File Upload Failed!</p>");
            }
            $("#message").append(data.message);
        }
    });
});

CONTROLLER

I've added some code that "reports" results to ajax and will display it on the upload page.

class Upload extends CI_Controller
{
    public function __construct()
    {
        parent::__construct();
        $this->load->helper(['form', 'url']);
    }

    public function index()
    {
        $this->load->view('upload_v');
    }

    public function post()
    {
        $this->load->library("upload");
        $this->upload->initialize(array(
                "upload_path" => './uploads/',
                'allowed_types' => 'gif|jpg|png|doc|txt',
                "overwrite" => FALSE,
                "max_filename" => 300,
                "encrypt_name" => TRUE,
        ));

        $successful = $this->upload->do_upload('userfile');

        if($successful)
        {
            $data = $this->upload->data();
            $image_file = $data['file_name'];
            $msg = "<p>File: {$image_file}</p>";
            $this->data_models->update($this->data->INFO, array("image" => $image_file));
        } else {
            $msg = $this->upload->display_errors();
        }

        echo json_encode(['result' => $successful, 'message' => $msg]);
    }

}

This will upload your file. Your work probably isn't done because I suspect that your are not saving all the file info you need to the db. That, and I suspect you are going to be surprised by the name of the uploaded file.

I suggest you study up on how PHP handles file uploads and examine some of the similar codeigniter related questions on file uploads here on SO.

回答2:

Another approach to this would be passing to PHP the file encoded in base64:

get the selected file from #userfile field using $('#userfile').prop('files')[0];
transform the contents of that file into a base64 encoded string using FileReader.readAsDataURL(). We're going to call this content; Here's a similar question showing how to do and expanding the answer & possibilities;
send the AJAX passing both the filename and content strings;
now on CI, fetch the POST data;
base64_decode() the content;
fwrite() the result into a file using the filename.

That way also you could avoid POSTing all form fields.

回答3:

try this.. Post data using FormData() formdata post file also. To get all your form inputs, including the type="file" you need to use FormData object.

$('#post').on('click', function (e) {
    var file_data = $("#userfile").prop("files")[0];      
    var form_data = new FormData();                  
    form_data.append("userfile", file_data)
    $.ajax({
            url: window.location.href+'/post',
            type: 'POST',
            data: form_data,
            async: false,
            success: function (data) {
                alert(data)
            },
            cache: false,
            contentType: false,
            processData: false
        });
   return false;
});

For more...https://abandon.ie/notebook/simple-file-uploads-using-jquery-ajax

回答4:

Controller

public function upload()
{
$this->load->library('upload');

if (isset($_FILES['myfile']) && !empty($_FILES['myfile']))
{
    if ($_FILES['myfile']['error'] != 4)
    {
         // Image file configurations
        $config['upload_path'] = './upload/';
        $config['allowed_types'] = 'jpg|jpeg|png';
        $this->upload->initialize($config);
        $this->upload->do_upload('myfile');
    }
  }
 }

View

<form id="myform" action="<?php base_url('controller/method'); ?>" method="post">
<input type="file" name="myfile">

("#myform").submit(function(evt){
evt.preventDefault();

var url = $(this).attr('action');
var formData = new FormData($(this)[0]);
$.ajax({
    url: url,
    type: 'POST',
    data: formData,
    processData: false,
    contentType: false,
    success: function (res) {
        console.log(res);
    },
    error: function (error) {
        console.log(error);
    }
}); // End: $.ajax()           

}); // End: submit()

Let me know if any query

回答5:

you need to submit the form not on click but on submit ... give the form an id and then on submit put ajax

HTML

<?php $attributes = array('id' => 'post'); ?>

<?php echo form_open_multipart(site_url("upload/post",$attributes), ?>
    <input type="file" id="userfile" name="userfile" value="">
    <button id="post">Submit</button>
  <?php echo form_close() ?>

JAVASCRIPT

$('#post').on('submit', function () {

    var formData = new FormData();
    formData.append("userfile",$("#userfile")[0].files[0]);

    $.ajax({
            url: window.location.href+'/post',
            type: "POST",
            data: formData
        });

CONTROLLERS

public function post() 
    {
        $this->load->library("upload");
        $file = $this->common->nohtml($this->input->post("userfile"));
    $this->upload->initialize(array( 
           "upload_path" => 'upload',
           "overwrite" => FALSE,
           "max_filename" => 300,
           "encrypt_name" => TRUE,
        ));

    $data = $this->upload->data();

    $image_file = $data['file_name'];

    $this->data_models->update($this->data->INFO, array(
      "image" => $image_file
        )
      );

}