如何设置使用simple_list_item_2一个ListView的两行?(How to set

2019-06-25 21:57发布

所以下面将创建一个ListView其中行有自己的“主”的TextView由值数组填充。

ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, 
    android.R.layout.simple_list_item_2, android.R.id.text1, values);

改变第三参数android.R.id.text2设置“次要”的TextView。 有没有简单的方法来设置这两个?

Answer 1:

据我所知simple_list_item_2包含包含两个TextViews一个TwoLineListItem。 ArrayAdapter是不会在这里工作,你要么必须创建一个自定义的适配器或使用一个支持它像SimpleCursorAdapter。

ListAdapter adapter = new SimpleCursorAdapter(
                 this,
                 android.R.layout.simple_list_item_2,
                 mCursor,     // Pass in the cursor to bind to.
                 new String[] {People.NAME, People.COMPANY}, // Array of cursor columns to bind to.
                 new int[] {android.R.id.text1, android.R.id.text2});  // Parallel array of which template objects to bind to those columns.

         // Bind to our new adapter.
         setListAdapter(adapter);

或者,如果你不想SimpleCursorAdapter你必须创建一个自定义ArrayAdapter或BaseAdapter

创建自定义ArrayAdapter,应用对象(有两项)阵列的自定义适配器,并且将其提供给getListView.setAdapter。

重写一个ArrayAdapter的getView方法来应用你的名字字符串TextViews在自定义列表行视图。

下面的代码片段会帮助你。

SampleActivity.java

package org.sample;

import java.util.ArrayList;

import android.app.ListActivity;
import android.content.Context;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.BaseAdapter;
import android.widget.TextView;
import android.widget.TwoLineListItem;

public class SampleActivity extends ListActivity {

    @Override
    public void onCreate(Bundle icicle) {
        super.onCreate(icicle);

        Person person;

        ArrayList<Person> persons = new ArrayList<Person>();

        person = new Person();
        person.setName("Vipul");
        person.setAge(20);
        persons.add(person);

        person = new Person();
        person.setName("Anil");
        person.setAge(22);
        persons.add(person);

        setListAdapter(new MyAdapter(this, persons));
    }

}

Person.java

class Person {
    String name;
    int age;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }

}

MyAdapter.java

class MyAdapter extends BaseAdapter {

    private Context context;
    private ArrayList<Person> persons;

    public MyAdapter(Context context, ArrayList<Person> persons) {
        this.context = context;
        this.persons = persons;
    }

    @Override
    public int getCount() {
        return persons.size();
    }

    @Override
    public Object getItem(int position) {
        return persons.get(position);
    }

    @Override
    public long getItemId(int position) {
        return 0;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {

        TwoLineListItem twoLineListItem;

        if (convertView == null) {
            LayoutInflater inflater = (LayoutInflater) context
                    .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            twoLineListItem = (TwoLineListItem) inflater.inflate(
                    android.R.layout.simple_list_item_2, null);
        } else {
            twoLineListItem = (TwoLineListItem) convertView;
        }

        TextView text1 = twoLineListItem.getText1();
        TextView text2 = twoLineListItem.getText2();

        text1.setText(persons.get(position).getName());
        text2.setText("" + persons.get(position).getAge());

        return twoLineListItem;
    }
}


Answer 2:

这个问题居高与谷歌,但我认为在给定的答案是太复杂。 正如指出的其他答案,所期望的功能可以使用ArrayAdapter一个非常简单的技巧来实现。

您可以覆盖一个ArrayAdapter的getView方法:

ArrayAdapter adapter = new ArrayAdapter(context, android.R.layout.simple_list_item_2, android.R.id.text1, list) {
  @Override
  public View getView(int position, View convertView, ViewGroup parent) {
    View view = super.getView(position, convertView, parent);
    TextView text1 = (TextView) view.findViewById(android.R.id.text1);
    TextView text2 = (TextView) view.findViewById(android.R.id.text2);

    text1.setText(persons.get(position).getName());
    text2.setText(persons.get(position).getAge());
    return view;
  }
};

如果你没有注意到:关键是要提供android.R.id.text1为(主要是不必要的)参数,否则调用super将导致异常。

此外,该解决方案不使用的TwoLineListItem ,这是在API 17弃用。



Answer 3:

希望这有助于您

ArrayAdapter<CustomObject> adapter = new ArrayAdapter<CustomObject> (_context, android.R.layout.simple_list_item_2, android.R.id.text1, listCustomObject) {

                                @Override
                                public View getView(int position,
                                        View convertView, ViewGroup parent) {
                                    View view = super.getView(position, convertView, parent);

                                    TextView text1 = (TextView) view.findViewById(android.R.id.text1);
                                    TextView text2 = (TextView) view.findViewById(android.R.id.text2);

                                    text1.setText(listCustomObject.get(position).getText1());

                                    text2.setText( listCustomObject.get(position).getText2() );

                                    return view;
                                }

                            };


Answer 4:

可以试试这个以及....

adapter = new ArrayAdapter(this,android.R.layout.simple_list_item_2,values){
            @Override
            public View getView(int position, View convertView, ViewGroup parent){

               TwoLineListItem   row = (TwoLineListItem)super.getView(position, convertView, parent);

                row.getText1().setText(values.get***());
                row.getText2().setText(values.get****());

                return row;
            }
        };
    setAdapter(adapter);


文章来源: How to set both lines of a ListView using simple_list_item_2?