Using return in ternary operator php

问题:

I'm trying to use return in a ternary operator, but receive an error:

Parse error: syntax error, unexpected T_RETURN 

Here's the code:

$e = $this->return_errors();
(!$e) ? '' : return array('false', $e);

Is this possible?

Thanks!

回答1:

This is the correct syntax:

return  !$e ? '' : array('false', $e);

回答2:

Close. You'd want return condition?a:b

回答3:

It doesn't work in most languages because return is a statement (like if, while, etc.), rather than an operator that can be nested in an expression. Following the same logic you wouldn't try to nest an if statement within an expression:

// invalid because 'if' is a statement, cannot be nested, and yields no result
func(if ($a) $b; else $c;); 

// valid because ?: is an operator that yields a result
func($a ? $b : $c); 

It wouldn't work for break and continue as well.

回答4:

No it's not possible, and it's also pretty confusing as compared to:

if($e) {
    return array('false', $e);
}

回答5:

No. But you can have a ternary expression for the return statement.

return (!$e) ? '' : array('false', $e);

Note: This may not be the desired logic. I'm providing it as an example.

回答6:

No, that's not possible. The following, however, is possible:

$e = $this->return_errors();
return ( !$e ) ? '' : array( false, $e );

Hope that helps.