改变图像基于点击的pygame的(change image based on click in py

我已经做了谷歌搜索，通过我的两个Python初学者书籍搜索以找到如何做到这一点。我认为它是一个简单的任务。基本上，我与蟒蛇pygame的工作。

我想，如果我点击button1_image，它改变button1select_image，对不对？如果你点击button2_image，它设置button1select_image回button1_image，并button2_image变化button2select_image。

因此，我想知道是，如果它是一个简单的if else语句或者是它要复杂得多。显然，按钮会做其他的事情以后，但我无法找到如何做这样的事情基础上，用户点击鼠标的教程。

# Button Mouse Click Image Change
# Demonstrates changing from one button image to another based on click of mouse.

from livewires import games, color

games.init(screen_width = 281, screen_height = 500, fps = 50)

button1_image = games.load_image("button1.png", transparent = False)
button1 = games.Sprite(image = button1_image, x = 28,y = 18)
games.screen.add(button1)

button1select_image = games.load_image("button1select.png", transparent = False)
button1select = games.Sprite(image = button1select_image, x = 28,y = 18)
games.screen.add(button1select)

button2_image = games.load_image("button2.png", transparent = False)
button2 = games.Sprite(image = button2_image, x = 56,y = 18)
games.screen.add(button2)

button2select_image = games.load_image("button2select.png", transparent = False)
button2select = games.Sprite(image = button2select_image, x = 56,y = 18)
games.screen.add(button2select)

games.screen.mainloop()

Answer 1:

在这里，我掀起这达到显示鼠标的工作原理。该生产线if event.button == 1:检查是否鼠标左键被按下，如果你想鼠标右键改变1到2。

import pygame, sys
from pygame.locals import *

TIMER = 30
SCREEN_X = 200
SCREEN_Y = 200

screen = pygame.display.set_mode((SCREEN_X, SCREEN_Y))
clock = pygame.time.Clock() #tick-tock

ending = button1 = button2 = False

corner1 = (28,18)  #Top Left corner of button 1
corner2 = (56,18)  #Top Left corner of button 2

image_length = 100 #length of the buttons
image_height = 100 #height of the buttons

counter = 0

#Main Loop:
while ending==False:
    counter+=1
    clock.tick(TIMER)
    for event in pygame.event.get():
        if event.type == KEYDOWN:
            if event.key == K_ESCAPE:
                ending=True # Time to leave
                print("Game Stopped Early by user")
        elif event.type == MOUSEBUTTONDOWN:
            if event.button == 1:
                mouse_x, mouse_y = event.pos
                if (mouse_x >= corner1[0]) and (mouse_x <= corner1[0]+image_length) and (mouse_y >= corner1[1]) and (mouse_y <= corner1[1]+image_height):
                    print ("Button one is selected")
                    button1=True
                    button2=False
                elif (mouse_x >= corner2[0]) and (mouse_x <= corner2[0]+image_length) and (mouse_y >= corner2[1]) and (mouse_y <= corner2[1]+image_height):
                    print ("Button two is selected")
                    button1=False
                    button2=True
                else:
                    print ("That's not a button")
                    button1=False
                    button2=False
    if counter == TIMER:  #prints the statements once a second
        counter=0
        if button1==True:
            print ("Button one is currently selected")
        elif button2==True:
            print ("Button two is currently selected")
        else:
            print ("No buttons currently selected")

在底部的打印报表。简单地使用按钮1或2所选择的图像，如果按钮1或BUTTON2变量分别是True 。所以你有两个图像未选定按钮如果都没有选的人会是。如果你不知道如何使用图像等，看看在这里： http://www.pygame.org/docs/这真的帮助了我。尝试一下你自己，如果你还停留堆栈交易所将仍然在这里为您的问题:)

希望能帮助到你

Answer 2:

下面是一些伪代码：

selected_button = None
buttons = [button1, button2]

...

for event in pygame.event.get():
  ...
  if event.type == MOUSEBUTTONDOWN:
      for b in buttons:
          if b.rect.collidepoint(event.pos):
              if selected_button == b:
                  # unselect this button
              else:
                  # unselect the old button (if there's one) and select this one
  ...