如何转换一个JSON数组Java列表。 我使用的是史云逊(How do I convert a

我试图将多个相同类型的对象转换成一个List中的Java。 例如，我的JSON是：

{
    "Example": [
        {
            "foo": "a1",
            "bar": "b1",
            "fubar": "c1"
        },
        {
            "foo": "a2",
            "bar": "b2",
            "fubar": "c2"
        },
        {
            "foo": "a3",
            "bar": "b3",
            "fubar": "c3"
        }
    ]
}

我有一个类：

public class Example {
    private String foo;
    private String bar;
    private String fubar;
    public Example(){};
    public void setFoo(String f){
        foo = f;
    }
    public void setBar(String b){
        bar = b;
    }
    public void setFubar(String f){
        fubar = f;
    }
...
}

我希望能够把JSON字符串我到列表Example对象。 我愿做这样的事情：

JSONParser parser = new JSONParser();
parser.addTypeHint(".Example[]", Example.class);
List<Example> result = parser.parse(List.class, json);

这样做，我得到一个错误：

Cannot set property Example on class java.util.ArrayList

Answer 1:

您不能转换这个JSON来List ，但你可以将此转换为Map 。
请参阅您的JSON String ：

...
"Example": [
        {
            "foo": "a1",
            "bar": "b1",
            "fubar": "c1"
        },
        {
            "foo": "a2",
            "bar": "b2",
            "fubar": "c2"
        },
        ...
]
}

这里的“实施例”是键（字符串）和值是实施例的列表对象。

试试这个：

 parser.addTypeHint("Example[]", Example.class);
 Map<String,List<Example>> result1 = parser.parse(Map.class, json);
 for (Entry<String, List<Example>> entry : result1.entrySet()) {
     for (Example example : entry.getValue()) {
          System.out.println("VALUE :->"+ example.getFoo());
     }
 }

的全码Example ：

import java.util.List;
import java.util.Map;
import java.util.Map.Entry;

import org.svenson.JSONParser;

public class Test {
    public static void main(String[] args) {
        JSONParser parser = new JSONParser();
        parser.addTypeHint(".Example[]", Example.class);
        String json = "{" + "\"Example\": [" + "{" + "\"foo\": \"a1\","
                + "\"bar\": \"b1\"," + "\"fubar\": \"c1\"" + "}," + "{"
                + "\"foo\": \"a2\"," + "\"bar\": \"b2\"," + "\"fubar\": \"c2\""
                + "}," + "{" + "\"foo\": \"a3\"," + "\"bar\": \"b3\","
                + "\"fubar\": \"c3\"" + "}" + "]" + "}\"";
        parser.addTypeHint("Example[]", Example.class);
        Map<String, List<Example>> result1 = parser.parse(Map.class, json);
        for (Entry<String, List<Example>> entry : result1.entrySet()) {
            for (Example example : entry.getValue()) {
                System.out.println("VALUE :->" + example.getFoo());
            }
        }
    }
}

public class Example {
    private String foo;
    private String bar;
    private String fubar;
    public Example(){}
    public void setFoo(String foo) {
        this.foo = foo;
    }
    public String getFoo() {
        return foo;
    }
    public void setBar(String bar) {
        this.bar = bar;
    }
    public String getBar() {
        return bar;
    }
    public void setFubar(String fubar) {
        this.fubar = fubar;
    }
    public String getFubar() {
        return fubar;
    }
}

输出 ：

VALUE :->a1
VALUE :->a2
VALUE :->a3

Answer 2:

我解决它通过修改我的JSON是形式：

[
    {
        "foo": "a1",
        "bar": "b1",
        "fubar": "c1"
    },
    {
        "foo": "a2",
        "bar": "b2",
        "fubar": "c2"
    },
    {
        "foo": "a3",
        "bar": "b3",
        "fubar": "c3"
    }
]

然后我用Java代码：

JSONParser parser = new JSONParser();
    ArrayList list = parser.parse(ArrayList.class, json);
    List<Example> result = new ArrayList<Example>();
    for(int i = 0 ; i < list.size() ; i++){
        HashMap<String, String> map = (HashMap) list.get(i);
        Example example = new Example();
        example.setFoo(map.get("foo"));
        example.setBar(map.get("bar"));
        example.setFubar(map.get("fubar"));
        result.add(example);
    }

Answer 3:

我有一个jsonstring是这样的：

[
{"author":"amahta","bookId":1,"bookName":"name"},
{"author":"amahta2","bookId":2,"bookName":"name2"}
]

并将其转换为列表中该代码片段：

List<BookVO> listdata = new ArrayList<BookVO>();

JSONArray jArray = JSONArray.fromObject(booklist);
if (jArray != null) {
    for (int i = 0; i < jArray.size(); i++) {
        JSONObject obj = JSONObject.fromObject(jArray.get(i));
        listdata.add(new BookVO(Long.valueOf(obj.get("bookId")), obj.get("bookName"), obj.get("author")));
    }
}

我使用net.sf.json-lib的jar文件。

Answer 4:

     String paymentMethod = "[{\"paymentType\":\"google_iap\",\"msisdn\":1486890084928,\"operator\":\"maroc_ma\",\"paymentMethod\":\"maroc_ma\",\"reactivationEnabled\":true }]";

     PaymentMethod mop = null;
        try {
            mop = mapper.readValue(paymentMethod, PaymentMethod.class);
        } catch (Exception e) {
            logger.warn("Error while parsing paymentMethod = " + paymentMethod + " \n" + e);
        }

     List<PaymentMethod> result = new ArrayList<PaymentMethod>();
     result.add(mop);

     billingInfo.setPaymentMethods(result);

文章来源: How do I convert a JSON array into a Java List. I'm using svenson