I have a WPF application in which a thread checks some value. In certain cases, I show a pop-up Window
in order to display a message. When I create this pop-up window in the thread, an exception is thrown by the pop-up window's constructor:
"The calling thread must be STA, because many UI components require this."
How do I resolve this error?
This is my code for creating the pop-up window:
// using System.Threading;
// using System.Windows.Threading;
Thread Messagethread = new Thread(new ThreadStart(delegate()
{
DispatcherOperation DispacherOP =
frmMassenger.Dispatcher.BeginInvoke(
DispatcherPriority.Normal,
new Action(delegate()
{
frmMassenger.Show();
}));
}));
Messagethread.Start();
For the thread that you're trying to start the GUI element in, you need to set the apartment state of the thread to STA BEFORE you start it.
Example:
myThread.SetApartmentState(ApartmentState.STA);
myThread.Start();
Absolutely Dispatcher
is only way to do something (in specific Thread) when we work with multi-threading in WPF!
But for work with Dispatcher we must know 2 things:
- Too many way to use Dispatcher like Dispatcher_Operation ,
[window.dispatcher] or etc.
- We must
call dispatcher in the main thread of app
(that thread is must be STA thread)
So for example: if we want show other window[wpf] in another thread, we can use this code:
Frmexample frmexample = new Frmexample();
Frmexample .Dispatcher.BeginInvoke
(System.Windows.Threading.DispatcherPriority.Normal,
(Action)(() =>
{
frmexample.Show();
//---or do any thing you want with that form
}
));
Tip: Remember - we can't access any fields or properties from out dispatcher, so use that wisely