How do I transpose a table in Pentaho Kettle from

问题:

I'm new to Pentaho and I need to transpose a table from rows to columns, but the first column doesn't contain the headers.

It looks something like this:

Jan/15  Feb/15  Mar/15  Apr/15
1.1     3.4     1.7     2.0
2.5     4.5     2.4     3.3

And I need to convert to a table like the on below:

Month   Value A  Value B
Jan/15  1.1      2.5
Feb/15  3.4      4.5
Mar/15  1.7      2.4
Apr/15  2.0      3.3

Someone knows how can I achieve this? Is there some step that could help or only through scripts?

回答1:

You have to add the value name (A and B) to the row. And then first do a Row Normaliser, to make rows. Then you have to Row denormaliser, to get the two different values on the same row.

Convert string date, to date for correct sort: