Clean way to exit declarative Jenkins pipeline as

问题:

I am looking for the cleanest way to exit a declarative Jenkins pipeline, with a success status. While exiting with an error is very neat using error step , I couldn't find any equal way to exit with success code. E.G:

stage('Should Continue?') {
  when {
    expression {skipBuild == true }
  }
  steps {
    echo ("Skiped Build")
    setBuildStatus("Build complete", "SUCCESS");
    // here how can I abort with sucess code?
    // Error Would have been:
    // error("Error Message")

  }
}
stage('Build') {
  steps {
    echo "my build..."
  }
}

For Example with a scripted build, I could achieve it with the following code:

if (shouldSkip == true) {
  echo ("'ci skip' spotted in all git commits. Aborting.")
  currentBuild.result = 'SUCCESS'
  return
}

While I am aware of the ability to add a script step to my declarative pipieline, I was hoping to find a cleaner way.

Another approach could be throwing an error and catch it somewhere down the line, but again it quite messy.

Is there a cleaner way?

回答1:

A solution that worked for me was to create a stage with sub-stages and put the check in the top level stage.

stage('Run if expression ') {
    when {
        expression { skipBuild != true }
    }
    stages {
        stage('Hello') {
            steps {
                echo "Hello there"
            }
        }
    }
}

So I put all the stages that I want to continue inside this stage. And everything else outside of it. In your case you would put all your build stages inside the stage with when check.