我碰到的东西,我终于想通了,跑了,但是认为可能有一个更有效的方式来完成它。
我有一个对象,它有许多属性(标题,副标题,纬度,经度,信息等)的(一个NSObject其中通过的MKAnnotation协议)。 我需要能够到这个对象传递给另一个对象,这要提取使用objectForKey方法从它的信息,作为一个NSDictionary(因为这是它是从另一个视图控制器获得)。
我落得这样做是创建一个新的NSMutableDictionary和使用的setObject:forKey上每件的重要信息传递,然后我刚刚通过新创建的字典。
有没有更简单的方法来做到这一点?
下面是相关的代码:
// sender contains a custom map annotation that has extra properties...
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([[segue identifier] isEqualToString:@"showDetailFromMap"])
{
DetailViewController *dest =[segue destinationViewController];
//make a dictionary from annotaion to pass info
NSMutableDictionary *myValues =[[NSMutableDictionary alloc] init];
//fill with the relevant info
[myValues setObject:[sender title] forKey:@"title"] ;
[myValues setObject:[sender subtitle] forKey:@"subtitle"];
[myValues setObject:[sender info] forKey:@"info"];
[myValues setObject:[sender pic] forKey:@"pic"];
[myValues setObject:[sender latitude] forKey:@"latitude"];
[myValues setObject:[sender longitude] forKey:@"longitude"];
//pass values
dest.curLoc = myValues;
}
}
在此先感谢您的集体智慧。
以下是我想出了,多亏了乡亲们,下面...
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([[segue identifier] isEqualToString:@"showDetailFromMap"])
{
DetailViewController *dest =[segue destinationViewController];
NSArray *myKeys = [NSArray arrayWithObjects:
@"title",@"subtitle",@"info",@"pic",@"latitude",@"longitude", nil];
//make a dictionary from annotaion to pass info
NSDictionary *myValues =[sender dictionaryWithValuesForKeys:myKeys];
//pass values
dest.curLoc = myValues;
}
}
而一个更简单的修复,如下面看到的...
使用valueForKey而不是对象键来检索信息。
Answer 1:
如果属性都有相同的名称用于访问字典中的项,那么你可能刚使用KVC,不得不valueForKey:
不是objectForKey
。
对于给定的这个词典范例
NSDictionary *annotation = [[NSDictionary alloc] initWithObjectsAndKeys:
@"A title", @"title", nil];
这个对象
@interface MyAnnotation : NSObject
@property (nonatomic, copy) NSString *title;
@end
如果我有字典的实例,或者它不会有问题MyAnnotation
我可以打电话
[annotation valueForKey:@"title"];
显然,工程的其他方式,以及如
[annotation setValue:@"A title" forKey:@"title"];
Answer 2:
当然可以! 使用objc运行时和KVC!
#import <objc/runtime.h>
@interface NSDictionary(dictionaryWithObject)
+(NSDictionary *) dictionaryWithPropertiesOfObject:(id) obj;
@end
@implementation NSDictionary(dictionaryWithObject)
+(NSDictionary *) dictionaryWithPropertiesOfObject:(id)obj
{
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
unsigned count;
objc_property_t *properties = class_copyPropertyList([obj class], &count);
for (int i = 0; i < count; i++) {
NSString *key = [NSString stringWithUTF8String:property_getName(properties[i])];
[dict setObject:[obj valueForKey:key] forKey:key];
}
free(properties);
return [NSDictionary dictionaryWithDictionary:dict];
}
@end
你会使用这样的:
MyObj *obj = [MyObj new];
NSDictionary *dict = [NSDictionary dictionaryWithPropertiesOfObject:obj];
NSLog(@"%@", dict);
Answer 3:
这是一个古老的职位和理查德·罗斯三世的回答是真正有用的,但在自定义对象的情况下(一个自定义的类还有一个自定义对象的话)。 然而,有时属性的其他对象等等,使得系列化有点复杂。
Details * details = [[Details alloc] init];
details.tomato = @"Tomato 1";
details.potato = @"Potato 1";
details.mangoCount = [NSNumber numberWithInt:12];
Person * person = [[Person alloc]init];
person.name = @"HS";
person.age = @"126 Years";
person.gender = @"?";
person.details = details;
对于这些类型的对象(多个自定义对象)转换成字典,我不得不修改理查德·罗斯III的回答:一点点。
+(NSDictionary *) dictionaryWithPropertiesOfObject:(id)obj
{
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
unsigned count;
objc_property_t *properties = class_copyPropertyList([obj class], &count);
for (int i = 0; i < count; i++) {
NSString *key = [NSString stringWithUTF8String:property_getName(properties[i])];
Class classObject = NSClassFromString([key capitalizedString]);
if (classObject) {
id subObj = [self dictionaryWithPropertiesOfObject:[obj valueForKey:key]];
[dict setObject:subObj forKey:key];
}
else
{
id value = [obj valueForKey:key];
if(value) [dict setObject:value forKey:key];
}
}
free(properties);
return [NSDictionary dictionaryWithDictionary:dict];
}
我希望这会帮助别人。 全归功于理查德·罗斯III。
Answer 4:
为了完成理查德·罗斯的方法,这与一个自定义对象的NSArray的作品。
+(NSDictionary *) dictionaryWithPropertiesOfObject:(id)obj
{
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
unsigned count;
objc_property_t *properties = class_copyPropertyList([obj class], &count);
for (int i = 0; i < count; i++) {
NSString *key = [NSString stringWithUTF8String:property_getName(properties[i])];
Class classObject = NSClassFromString([key capitalizedString]);
id object = [obj valueForKey:key];
if (classObject) {
id subObj = [self dictionaryWithPropertiesOfObject:object];
[dict setObject:subObj forKey:key];
}
else if([object isKindOfClass:[NSArray class]])
{
NSMutableArray *subObj = [NSMutableArray array];
for (id o in object) {
[subObj addObject:[self dictionaryWithPropertiesOfObject:o] ];
}
[dict setObject:subObj forKey:key];
}
else
{
if(object) [dict setObject:object forKey:key];
}
}
free(properties);
return [NSDictionary dictionaryWithDictionary:dict];
}
Answer 5:
有这么多的解决方案,并没有什么工作对我来说,因为我有一个复杂的嵌套对象结构。 该解决方案采用由理查德和达米安的东西,但作为达明的解决方案是依赖于命名键作为类名即兴。
这里是头
@interface NSDictionary (PropertiesOfObject)
+(NSDictionary *) dictionaryWithPropertiesOfObject:(id)obj;
@end
这里是.m文件
@implementation NSDictionary (PropertiesOfObject)
static NSDateFormatter *reverseFormatter;
+ (NSDateFormatter *)getReverseDateFormatter {
if (!reverseFormatter) {
NSLocale *locale = [[NSLocale alloc] initWithLocaleIdentifier:@"en_US_POSIX"];
reverseFormatter = [[NSDateFormatter alloc] init];
[reverseFormatter setDateFormat:@"yyyy-MM-dd'T'HH:mm:ss.SSS'Z'"];
[reverseFormatter setLocale:locale];
}
return reverseFormatter;
}
+ (NSDictionary *)dictionaryWithPropertiesOfObject:(id)obj {
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
unsigned count;
objc_property_t *properties = class_copyPropertyList([obj class], &count);
for (int i = 0; i < count; i++) {
NSString *key = [NSString stringWithUTF8String:property_getName(properties[i])];
id object = [obj valueForKey:key];
if (object) {
if ([object isKindOfClass:[NSArray class]]) {
NSMutableArray *subObj = [NSMutableArray array];
for (id o in object) {
[subObj addObject:[self dictionaryWithPropertiesOfObject:o]];
}
dict[key] = subObj;
}
else if ([object isKindOfClass:[NSString class]]) {
dict[key] = object;
} else if ([object isKindOfClass:[NSDate class]]) {
dict[key] = [[NSDictionary getReverseDateFormatter] stringFromDate:(NSDate *) object];
} else if ([object isKindOfClass:[NSNumber class]]) {
dict[key] = object;
} else if ([[object class] isSubclassOfClass:[NSObject class]]) {
dict[key] = [self dictionaryWithPropertiesOfObject:object];
}
}
}
return dict;
}
@end
Answer 6:
您也可以使用NSObject+APObjectMapping
类别,它可在GitHub上: https://github.com/aperechnev/APObjectMapping
这是一个退出容易。 刚刚描述类的映射规则:
#import <Foundation/Foundation.h>
#import "NSObject+APObjectMapping.h"
@interface MyCustomClass : NSObject
@property (nonatomic, strong) NSNumber * someNumber;
@property (nonatomic, strong) NSString * someString;
@end
@implementation MyCustomClass
+ (NSMutableDictionary *)objectMapping {
NSMutableDictionary * mapping = [super objectMapping];
if (mapping) {
NSDictionary * objectMapping = @{ @"someNumber": @"some_number",
@"someString": @"some_string" };
}
return mapping
}
@end
然后你可以在你的对象容易映射到词典:
MyCustomClass * myObj = [[MyCustomClass alloc] init];
myObj.someNumber = @1;
myObj.someString = @"some string";
NSDictionary * myDict = [myObj mapToDictionary];
您也可以从字典解析你的对象:
NSDictionary * myDict = @{ @"some_number": @123,
@"some_string": @"some string" };
MyCustomClass * myObj = [[MyCustomClass alloc] initWithDictionary:myDict];
文章来源: Obj-C easy method to convert from NSObject with properties to NSDictionary?