我正在从别人的库函数美孚在单线程应用程序目前。 大部分时间,我做出美孚通话,它的真快,有些时候,我做出美孚打电话,它永远。 我不是一个有耐心的人,如果foo是要采取永远,我想停止美孚的执行,而不是用这些参数来调用它。
什么是叫富控制的方式的最佳方式(我目前的环境是POSIX / C ++),这样我可以若干秒后停止执行。 我觉得在这里做正确的事情就是创建第二个线程调用富,而在我的主线程创建一个定时器功能,如果它运行的时间,最终将信号的第二个线程。
难道还有其他的,更倾向于模型(和解决方案)? 如果不是,将提高的Signals2库和线程做的伎俩?
您可以拨打美孚与超时第二个线程。 例如:
#include <boost/date_time.hpp>
#include <boost/thread/thread.hpp>
boost::posix_time::time_duration timeout = boost::posix_time::milliseconds(500);
boost::thread thrd(&Foo);
if (thrd.timed_join(timeout))
{
//finished
}
else
{
//Not finished;
}
您可以使用下面的类:
class timer
{
typedef boost::signals2::signal<void ()> timeout_slot;
public:
typedef timeout_slot::slot_type timeout_slot_t;
public:
timer() : _interval(0), _is_active(false) {};
timer(int interval) : _interval(interval), _is_active(false) {};
virtual ~timer() { stop(); };
inline boost::signals2::connection connect(const timeout_slot_t& subscriber) { return _signalTimeout.connect(subscriber); };
void start()
{
boost::lock_guard<boost::mutex> lock(_guard);
if (is_active())
return; // Already executed.
if (_interval <= 0)
return;
_timer_thread.interrupt();
_timer_thread.join();
timer_worker job;
_timer_thread = boost::thread(job, this);
_is_active = true;
};
void stop()
{
boost::lock_guard<boost::mutex> lock(_guard);
if (!is_active())
return; // Already executed.
_timer_thread.interrupt();
_timer_thread.join();
_is_active = false;
};
inline bool is_active() const { return _is_active; };
inline int get_interval() const { return _interval; };
void set_interval(const int msec)
{
if (msec <= 0 || _interval == msec)
return;
boost::lock_guard<boost::mutex> lock(_guard);
// Keep timer activity status.
bool was_active = is_active();
if (was_active)
stop();
// Initialize timer with new interval.
_interval = msec;
if (was_active)
start();
};
protected:
friend struct timer_worker;
// The timer worker thread.
struct timer_worker
{
void operator()(timer* t)
{
boost::posix_time::milliseconds duration(t->get_interval());
try
{
while (1)
{
boost::this_thread::sleep<boost::posix_time::milliseconds>(duration);
{
boost::this_thread::disable_interruption di;
{
t->_signalTimeout();
}
}
}
}
catch (boost::thread_interrupted const& )
{
// Handle the thread interruption exception.
// This exception raises on boots::this_thread::interrupt.
}
};
};
protected:
int _interval;
bool _is_active;
boost::mutex _guard;
boost::thread _timer_thread;
// Signal slots
timeout_slot _signalTimeout;
};
使用的一个示例:
void _test_timer_handler()
{
std::cout << "_test_timer_handler\n";
}
BOOST_AUTO_TEST_CASE( test_timer )
{
emtorrus::timer timer;
BOOST_CHECK(!timer.is_active());
BOOST_CHECK(timer.get_interval() == 0);
timer.set_interval(1000);
timer.connect(_test_timer_handler);
timer.start();
BOOST_CHECK(timer.is_active());
std::cout << "timer test started\n";
boost::this_thread::sleep<boost::posix_time::milliseconds>(boost::posix_time::milliseconds(5500));
timer.stop();
BOOST_CHECK(!timer.is_active());
BOOST_CHECK(_test_timer_count == 5);
}
您也可以直接调用该函数,并捕捉SIGALRM前设置闹钟。
弗拉德,优秀的文章! 您的代码编译和精美的作品。 我实现了一个软件看门狗定时器用它。 我做了一些修改:
- 为防止指针腐烂,存储在升压:: shared_ptr的信号,并通过这线程worker,而不是一个弱指针的计时类。 这省去了线程worker是朋友结构,保证了信号是在内存中。
- 添加参数_is_periodic允许呼叫者选择工作线程是否是周期性的,或者如果它期满后终止。
- 商店_is_active,_interval和_is_periodic中的boost ::原子,使线程安全的访问。
- 缩小互斥锁的范围。
- 添加reset()方法为“踢”计时器,防止它发出到期信号。
这些变化适用于:
#include <atomic>
#include <boost/signals2.hpp>
#include <boost/thread.hpp>
class IntervalThread
{
using interval_signal = boost::signals2::signal<void(void)>;
public:
using interval_slot_t = interval_signal::slot_type;
IntervalThread(const int interval_ms = 60)
: _interval_ms(interval_ms),
_is_active(false),
_is_periodic(false),
_signal_expired(new interval_signal()) {};
inline ~IntervalThread(void) { stop(); };
boost::signals2::connection connect(const interval_slot_t &subscriber)
{
// thread-safe: signals2 obtains a mutex on connect()
return _signal_expired->connect(subscriber);
};
void start(void)
{
if (is_active())
return; // Already executed.
if (get_interval_ms() <= 0)
return;
boost::lock_guard<boost::mutex> lock(_timer_thread_guard);
_timer_thread.interrupt();
_timer_thread.join();
_timer_thread = boost::thread(timer_worker(),
static_cast<int>(get_interval_ms()),
static_cast<bool>(is_periodic()),
_signal_expired);
_is_active = true;
};
void reset(void)
{
if (is_active())
stop();
start();
}
void stop(void)
{
if (!is_active())
return; // Already executed.
boost::lock_guard<boost::mutex> lock(_timer_thread_guard);
_timer_thread.interrupt();
_timer_thread.join();
_is_active = false;
};
inline bool is_active(void) const { return _is_active; };
inline int get_interval_ms(void) const { return _interval_ms; };
void set_interval_ms(const int interval_ms)
{
if (interval_ms <= 0 || get_interval_ms() == interval_ms)
return;
// Cache timer activity state.
const bool was_active = is_active();
// Initialize timer with new interval.
if (was_active)
stop();
_interval_ms = interval_ms;
if (was_active)
start();
};
inline bool is_periodic(void) const { return _is_periodic; }
inline void set_periodic(const bool is_periodic = true) { _is_periodic = is_periodic; }
private:
// The timer worker for the interval thread.
struct timer_worker {
void operator()(const int interval_ms, const bool is_periodic, boost::shared_ptr<interval_signal> signal_expired)
{
boost::posix_time::milliseconds duration(interval_ms);
try {
do {
boost::this_thread::sleep<boost::posix_time::milliseconds>(duration);
{
boost::this_thread::disable_interruption di;
signal_expired->operator()();
}
} while (is_periodic);
} catch (const boost::thread_interrupted &) {
// IntervalThread start(), stop() and reset() throws boost::this_thread::interrupt,
// which is expected since this thread is interrupted. No action neccessary.
}
};
};
std::atomic<int> _interval_ms; // Interval, in ms
std::atomic<bool> _is_active; // Is the timed interval active?
std::atomic<bool> _is_periodic; // Is the timer periodic?
boost::mutex _timer_thread_guard;
boost::thread _timer_thread;
// The signal to call on interval expiration.
boost::shared_ptr<interval_signal> _signal_expired;
};
文章来源: Can I create a software watchdog timer thread in C++ using Boost Signals2 and Threads?