How to print $ with php

问题:

Basically I have a block of html that I want to echo to the page and the html has the $ sign in it and the php thinks it is a variable so $1 is treated as the variable not the value and is not displayed.

There is the standard answers here but none are working: PHP: How to get $ to print using echo

My next idea is to split the string at the $ and echo each part out.

Here is the code I have tried echo and print.

foreach ($rows as $rowmk) {
    $s = $rowmk->longdescription;
    //$s = str_replace('$', '@', $s);
    $s = str_replace('$', '\$', $s);
    //echo  "$s" . "<br>";
    print $s;
}

All help appreciated.

OK I solved by using the character code value for $

foreach ($rows as $rowmk) {
    $s = $rowmk->longdescription;       
    $s = str_replace('$', '$', $s);
    echo  $s . "<br>";
}

I figured I should just post it anyway.

Thanks,

Mat

回答1:

You're doing it in the wrong place. Variable interpolating is done when double quoted string literal (which in your case is stored within $rowmk->longdescription is daclared. Once it's done, you can't really do anything to get your $s back.

Solution, do proper escaping, when you declare the string.

回答2:

Or you could echo string literal using single quotes...

<?php

echo 'Give me $1';

?>

will print:

Give me $1

PHP string docs:

http://php.net/manual/en/language.types.string.php

Side note - the link you provide has many answers that would work perfectly. How are you applying them in a way that doesn't work?

回答3:

Just use a single quoted string.

$foo = 'Hello';
echo '$foo'; // $foo
echo "$foo"; // Hello

回答4:

I assume you read your rows from a database. Dollar Signs inside these strings will not be interpolated by php. Here's a little test script to try it out:

  // you'd first have to set the three variables according to your database
  $dbh = new PDO($DSN, $DB_USER, $DB_PASS);

  // create a table and insert a string containing a dollar sign
  $dbh->exec('CREATE TABLE IF NOT EXISTS some_text ( longdescription VARCHAR( 255 ))');
  $dbh->exec('INSERT INTO some_text ( longdescription ) VALUES ( "10 $" )');

  // query all the data from the table
  $query =$dbh->query("SELECT * FROM some_text");
  $rows = $query->fetchAll(PDO::FETCH_CLASS);

  // loop over all the rows (as in your example) and output the rows
  // no problem at all
  foreach ($rows as $rowmk) {
    $s = $rowmk->longdescription;
    echo  $s . "<br>";
  }

回答5:

I did it using this

echo "$" . "VariableName";